Easy Resilience Patterns

Timeout with Fallback

Create a Mono that simulates a slow service by delaying 5 seconds. Apply a timeout of 1 second and provide a fallback value "Timeout fallback" using onErrorReturn. Subscribe and print.

Note: For Piston execution, simulate with Mono.delay and .timeout().

Expected

Timeout fallback

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Main.kt

Timeout with Fallback

easy⏱ 15 minkotlinreactorchallengeresilience

Create a Mono that simulates a slow service by delaying 5 seconds. Apply a timeout of 1 second and provide a fallback value "Timeout fallback" using onErrorReturn. Subscribe and print.

Note: For Piston execution, simulate with Mono.delay and .timeout().

Why this works

timeout() sets a maximum time to wait for the next signal. If the timeout expires, it emits a TimeoutException. Combined with onErrorReturn(), this creates a resilient pattern that provides a fallback for slow services.

Expected output

Timeout fallback

Timeout with Fallback

Create a Mono that simulates a slow service by delaying 5 seconds. Apply a timeout of 1 second and provide a fallback value "Timeout fallback" using onErrorReturn. Subscribe and print.

Note: For Piston execution, simulate with Mono.delay and .timeout().

Expected

Timeout fallback

Timeout with Fallback

easy⏱ 15 minkotlinreactorchallengeresilience

Create a Mono that simulates a slow service by delaying 5 seconds. Apply a timeout of 1 second and provide a fallback value "Timeout fallback" using onErrorReturn. Subscribe and print.

Note: For Piston execution, simulate with Mono.delay and .timeout().

Why this works

Expected output

Timeout fallback